玛氪宕·梦魔(Markdown Memo),使用Markdown的云端备忘录,百度IFE的RIA启航班的不合格的作业,才……才没有什么阴谋呢! 源gitee链接https://gitee.com/arathi/MarkdownMemo?_from=gitee_search
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<title>Tex 科学公式语言 (TeX/LaTeX) - Editor.md examples</title>
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<header>
<h1>Tex 科学公式语言 (TeX/LaTeX)</h1>
<p>Based on KaTeX.js:<a href="http://khan.github.io/KaTeX/" target="_blank">http://khan.github.io/KaTeX/</a></p>
<p>P.S. Default using CloudFlare KaTeX's CDN. (注:默认使用 CloudFlare 的 CDN,有时加载速度会比较慢,可自定义加载地址。)</p>
<br/>
<p><a href="https://jsperf.com/katex-vs-mathjax" target="_blank">KaTeX vs MathJax</a></p>
</header>
<div id="test-editormd">
<textarea style="display:none;">[TOC]
#### Setting
{
tex : true
}
#### Custom KaTeX source URL
```javascript
// Default using CloudFlare KaTeX's CDN
// You can custom url
editormd.katexURL = {
js : "your url", // default: //cdnjs.cloudflare.com/ajax/libs/KaTeX/0.3.0/katex.min
css : "your url" // default: //cdnjs.cloudflare.com/ajax/libs/KaTeX/0.3.0/katex.min
};
```
#### Examples
##### 行内的公式 Inline
$$E=mc^2$$
Inline 行内的公式 $$E=mc^2$$ 行内的公式,行内的$$E=mc^2$$公式。
$$c = \\pm\\sqrt{a^2 + b^2}$$
$$x &gt; y$$
$$f(x) = x^2$$
$$\alpha = \sqrt{1-e^2}$$
$$\(\sqrt{3x-1}+(1+x)^2\)$$
$$\sin(\alpha)^{\theta}=\sum_{i=0}^{n}(x^i + \cos(f))$$
$$\\dfrac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}$$
$$f(x) = \int_{-\infty}^\infty\hat f(\xi)\,e^{2 \pi i \xi x}\,d\xi$$
$$\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }$$
$$\displaystyle \left( \sum\_{k=1}^n a\_k b\_k \right)^2 \leq \left( \sum\_{k=1}^n a\_k^2 \right) \left( \sum\_{k=1}^n b\_k^2 \right)$$
$$a^2$$
$$a^{2+2}$$
$$a_2$$
$${x_2}^3$$
$$x_2^3$$
$$10^{10^{8}}$$
$$a_{i,j}$$
$$_nP_k$$
$$c = \pm\sqrt{a^2 + b^2}$$
$$\frac{1}{2}=0.5$$
$$\dfrac{k}{k-1} = 0.5$$
$$\dbinom{n}{k} \binom{n}{k}$$
$$\oint_C x^3\, dx + 4y^2\, dy$$
$$\bigcap_1^n p \bigcup_1^k p$$
$$e^{i \pi} + 1 = 0$$
$$\left ( \frac{1}{2} \right )$$
$$x_{1,2}=\frac{-b\pm\sqrt{\color{Red}b^2-4ac}}{2a}$$
$${\color{Blue}x^2}+{\color{YellowOrange}2x}-{\color{OliveGreen}1}$$
$$\textstyle \sum_{k=1}^N k^2$$
$$\dfrac{ \tfrac{1}{2}[1-(\tfrac{1}{2})^n] }{ 1-\tfrac{1}{2} } = s_n$$
$$\binom{n}{k}$$
$$0+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+\cdots$$
$$\sum_{k=1}^N k^2$$
$$\textstyle \sum_{k=1}^N k^2$$
$$\prod_{i=1}^N x_i$$
$$\textstyle \prod_{i=1}^N x_i$$
$$\coprod_{i=1}^N x_i$$
$$\textstyle \coprod_{i=1}^N x_i$$
$$\int_{1}^{3}\frac{e^3/x}{x^2}\, dx$$
$$\int_C x^3\, dx + 4y^2\, dy$$
$${}_1^2\!\Omega_3^4$$
##### 多行公式 Multi line
> \`\`\`math or \`\`\`latex or \`\`\`katex
```math
f(x) = \int_{-\infty}^\infty
\hat f(\xi)\,e^{2 \pi i \xi x}
\,d\xi
```
```math
\displaystyle
\left( \sum\_{k=1}^n a\_k b\_k \right)^2
\leq
\left( \sum\_{k=1}^n a\_k^2 \right)
\left( \sum\_{k=1}^n b\_k^2 \right)
```
```math
\dfrac{
\tfrac{1}{2}[1-(\tfrac{1}{2})^n] }
{ 1-\tfrac{1}{2} } = s_n
```
```katex
\displaystyle
\frac{1}{
\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{
\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {
1+\frac{e^{-6\pi}}
{1+\frac{e^{-8\pi}}
{1+\cdots} }
}
}
```
```latex
f(x) = \int_{-\infty}^\infty
\hat f(\xi)\,e^{2 \pi i \xi x}
\,d\xi
```
#### KaTeX vs MathJax
[https://jsperf.com/katex-vs-mathjax](https://jsperf.com/katex-vs-mathjax "KaTeX vs MathJax")
</textarea>
</div>
</div>
<script src="js/jquery.min.js"></script>
<script src="../editormd.js"></script>
<script type="text/javascript">
$(function() {
var testEditor = editormd("test-editormd", {
width: "90%",
height: 640,
path : '../lib/',
tex : true
});
});
</script>
</body>
</html>