玛氪宕·梦魔(Markdown Memo)，使用Markdown的云端备忘录，百度IFE的RIA启航班的不合格的作业，才……才没有什么阴谋呢！
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184 lines
5.6 KiB
184 lines
5.6 KiB
11 years ago
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<!doctype html>
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<title>CodeMirror: Ruby mode</title>
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<meta charset="utf-8"/>
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<link rel=stylesheet href="../../doc/docs.css">
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<link rel="stylesheet" href="../../lib/codemirror.css">
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<script src="../../lib/codemirror.js"></script>
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<script src="../../addon/edit/matchbrackets.js"></script>
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<script src="ruby.js"></script>
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<style>
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.CodeMirror {border-top: 1px solid black; border-bottom: 1px solid black;}
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.cm-s-default span.cm-arrow { color: red; }
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</style>
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<div id=nav>
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<a href="http://codemirror.net"><h1>CodeMirror</h1><img id=logo src="../../doc/logo.png"></a>
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<ul>
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<li><a href="../../index.html">Home</a>
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<li><a href="../../doc/manual.html">Manual</a>
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<li><a href="https://github.com/codemirror/codemirror">Code</a>
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</ul>
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<ul>
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<li><a href="../index.html">Language modes</a>
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<li><a class=active href="#">Ruby</a>
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</ul>
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</div>
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<article>
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<h2>Ruby mode</h2>
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<form><textarea id="code" name="code">
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# Code from http://sandbox.mc.edu/~bennet/ruby/code/poly_rb.html
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#
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# This program evaluates polynomials. It first asks for the coefficients
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# of a polynomial, which must be entered on one line, highest-order first.
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# It then requests values of x and will compute the value of the poly for
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# each x. It will repeatly ask for x values, unless you the user enters
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# a blank line. It that case, it will ask for another polynomial. If the
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# user types quit for either input, the program immediately exits.
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#
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#
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# Function to evaluate a polynomial at x. The polynomial is given
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# as a list of coefficients, from the greatest to the least.
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def polyval(x, coef)
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sum = 0
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coef = coef.clone # Don't want to destroy the original
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while true
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sum += coef.shift # Add and remove the next coef
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break if coef.empty? # If no more, done entirely.
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sum *= x # This happens the right number of times.
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end
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return sum
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end
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#
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# Function to read a line containing a list of integers and return
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# them as an array of integers. If the string conversion fails, it
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# throws TypeError. If the input line is the word 'quit', then it
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# converts it to an end-of-file exception
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def readints(prompt)
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# Read a line
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print prompt
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line = readline.chomp
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raise EOFError.new if line == 'quit' # You can also use a real EOF.
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# Go through each item on the line, converting each one and adding it
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# to retval.
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retval = [ ]
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for str in line.split(/\s+/)
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if str =~ /^\-?\d+$/
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retval.push(str.to_i)
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else
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raise TypeError.new
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end
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end
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return retval
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end
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#
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# Take a coeff and an exponent and return the string representation, ignoring
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# the sign of the coefficient.
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def term_to_str(coef, exp)
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ret = ""
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# Show coeff, unless it's 1 or at the right
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coef = coef.abs
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ret = coef.to_s unless coef == 1 && exp > 0
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ret += "x" if exp > 0 # x if exponent not 0
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ret += "^" + exp.to_s if exp > 1 # ^exponent, if > 1.
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return ret
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end
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#
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# Create a string of the polynomial in sort-of-readable form.
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def polystr(p)
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# Get the exponent of first coefficient, plus 1.
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exp = p.length
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# Assign exponents to each term, making pairs of coeff and exponent,
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# Then get rid of the zero terms.
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p = (p.map { |c| exp -= 1; [ c, exp ] }).select { |p| p[0] != 0 }
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# If there's nothing left, it's a zero
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return "0" if p.empty?
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# *** Now p is a non-empty list of [ coef, exponent ] pairs. ***
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# Convert the first term, preceded by a "-" if it's negative.
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result = (if p[0][0] < 0 then "-" else "" end) + term_to_str(*p[0])
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# Convert the rest of the terms, in each case adding the appropriate
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# + or - separating them.
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for term in p[1...p.length]
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# Add the separator then the rep. of the term.
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result += (if term[0] < 0 then " - " else " + " end) +
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term_to_str(*term)
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end
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return result
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end
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#
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# Run until some kind of endfile.
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begin
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# Repeat until an exception or quit gets us out.
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while true
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# Read a poly until it works. An EOF will except out of the
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# program.
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print "\n"
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begin
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poly = readints("Enter a polynomial coefficients: ")
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rescue TypeError
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print "Try again.\n"
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retry
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end
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break if poly.empty?
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# Read and evaluate x values until the user types a blank line.
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# Again, an EOF will except out of the pgm.
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while true
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# Request an integer.
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print "Enter x value or blank line: "
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x = readline.chomp
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break if x == ''
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raise EOFError.new if x == 'quit'
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# If it looks bad, let's try again.
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if x !~ /^\-?\d+$/
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print "That doesn't look like an integer. Please try again.\n"
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next
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end
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# Convert to an integer and print the result.
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x = x.to_i
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print "p(x) = ", polystr(poly), "\n"
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print "p(", x, ") = ", polyval(x, poly), "\n"
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end
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end
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rescue EOFError
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print "\n=== EOF ===\n"
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rescue Interrupt, SignalException
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print "\n=== Interrupted ===\n"
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else
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print "--- Bye ---\n"
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end
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</textarea></form>
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<script>
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var editor = CodeMirror.fromTextArea(document.getElementById("code"), {
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mode: "text/x-ruby",
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matchBrackets: true,
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indentUnit: 4
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});
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</script>
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<p><strong>MIME types defined:</strong> <code>text/x-ruby</code>.</p>
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<p>Development of the CodeMirror Ruby mode was kindly sponsored
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by <a href="http://ubalo.com/">Ubalo</a>.</p>
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</article>
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